Answer:
|7000 - w| < 1000
Step-by-step explanation:
6000 < w < 8000
Subtract 7000 from the three "sides."
-1000 < w - 7000 < 1000
|w - 7000| < 1000
|7000 - w| < 1000
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
111630
Step-by-step explanation:
<span>2(3z-2)+8=34
6z - 4 + 8 = 34
6z + 4 = 34
6z = 34 -4
6z = 30
z =30/6
z = 5
answer </span><span>D. z=5</span>
