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alexandr1967 [171]
3 years ago
15

Help plz with Algebra question I attached a file

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

x=4.63

Step-by-step explanation:

Area = (1/2) (base) (height)

20 = (1/2) (x+4) (x)

40 = x²+4x

x²+4x-40=0

Put in quadratic equation:

x=\frac{-4(+/-)\sqrt{4^{2}-4(1)(-40) } }{2(1)}

x=\frac{-4(+/-)\sqrt{176} }{2}

x=4.63324958071 or x=-8.63324958071

Since x can't be negative in this case we take our answer to be 4.63324958071, which rounds to 4.63

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30

Step-by-step explanation:

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Dvide. Give the quotient and the remainder.<br> 838/8
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quotion is 104 and remainder is 6

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2 years ago
A cylindrical canister contains 3 tennis balls. Its height is 8.75 inches and its radius is 1.5. The diameter of one tennis ball
Rudiy27
Find Volume of 1 tennis ball:----------------------------------------------Volume of 1 tennis ball = 4/3 x 3.14 x (2.5 ÷ 2)³
Volume of 1 tennis ball = 8.18 in³
----------------------------------------------Find Volume of 3 tennis balls:----------------------------------------------Volume of 3 tennis balls = 8.18 x 3 = 24.54 in³
----------------------------------------------Find Volume of teh cylindrical canister:----------------------------------------------Volume of the cylindrical canister = 3.14 x 1.5² x (2.5 x 3)
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4 0
3 years ago
Read 2 more answers
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

-----------------------------------------------------------------------------------
Cancel the factors
-----------------------------------------------------------------------------------
= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

-----------------------------------------------------------------------------------
Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
Find the value of f(–3) and g(3) if f(x) = –6x + 3 and g(x) = 3x + 21x–3.
ryzh [129]

Answer:

f(-3) = 21

g(3) = 69

Step-by-step explanation:

We have been given the following functions;

f(x) = –6x + 3

g(x) = 3x + 21x–3.

To find f(-3) , we simply substitute x = -3 in the function of f(x);

f(-3) = -6(-3) + 3

      = 21

To find g(3) , substitute x = 3 in the function of g(x);

g(3) = 3(3) +21(3) - 3

      = 69

3 0
3 years ago
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