Nathan has exactly 407 cards from national league however since you have to estimate with that rate the answer is 400.
702 (Total Cards) × 0.58 = 407. 16
407.16 (Rounded to 100) = 400
702 × 0.58 = 407.16 = 400
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Answer:
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Answer:
C(p) = 4,96 (in thousands of dollars)
l = 2980 $ invest in labor
k = 2980 $ invest in equipment
Step-by-step explanation:
Information we have:
Monthly output P = 450*l*k ⇒ k = P/450*l
But the production need to be 4000
Then k = 4000/450*l
Cost of production = l * k (in thousands of dollars)
C(l) = l + 4000/450*l
Taking derivatives (both members of the equation)
C´(l) = 1 - 400 /45*l² ⇒ C´(l) = 0 ⇒ 1 - 400/45l² = 0
45*l² - 400 = 0 ⇒ l² = 400/45
l = 2.98 (in thousands of dollars)
l = 2980 $ And
k = 400/45*l ⇒ k 400/45*2.98
k = 2.98 (in thousands of dollars)
C(p) = l + k
C(p) = 2980 + 2980
C(p) = 5960 $
Answer:
area= 59.5 perimeter=31.6
Step-by-step explanation:
the area of the square is 49 because 7x7=49 and the area of the triangle is 3x7/2 because it is half of a rectangle so it is 10.5 + 49 = 59.5 and perimeter you add all the sides so 3+7.6+7+7+7= 31.6
Answer:
a) Cancellations are independent and similar to arrivals.
b) 22.31% probability that no cancellations will occur on a particular Wednesday
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Mean rate of 1.5 per day on a typical Wednesday.
This means that 
(a) Justify the use of the Poisson model.
Each wednesday is independent of each other, and each wednesday has the same mean number of cancellations.
So the answer is:
Cancellations are independent and similar to arrivals.
(b) What is the probability that no cancellations will occur on a particular Wednesday
This is P(X = 0).
22.31% probability that no cancellations will occur on a particular Wednesday
