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3 years ago

Find xy if x + y=3, x^2 + y^2 = 5

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer:

mark me

Step-by-step explanation:

x+y=3

x=3-y

putting the value of x

in this

x²+y²=5

(3-y) ²+y²=5

9-6y+y²+y²=5

2y²-6y+9-5=0

2y²-6y+4=0

2y²-4y-2y+4=0

2y(y-2)-2(y-2)=0

(2y-2) (y-2) =0

2y-2=0 or y-2=0

y=1 or y=2

so x=2 or 1

so x×y=2×1 or 1×2=2

I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

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3 years ago

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ANSWER

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EXPLANATION

The sum of the first $n$ terms of a geometric sequence is given by;

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Read 2 more answers

Calculate the average rate of change for the function f(x)=x^4+3x^3-5x^2+2x-2, from x=-1 to x=1

borishaifa [10]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= x^4+3x^3-5x^2+2x-2 \qquad 
\begin{cases}
x_1=-1\\
x_2=1
\end{cases}\implies \cfrac{f(1)-f(-1)}{1-(-1)}
\\\\\\
\cfrac{[1+3-5+2-2]~~-~~[1-3-5-2-2]}{1+1}\implies \cfrac{[-1]~~-~~[-11]}{2}
\\\\\\
\cfrac{-1+11}{2}\implies \cfrac{10}{2}\implies 5$

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3 years ago