Answer:
x = 20
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Answer:
1. 650, 700 2. 840, 800 3. 370, 400 4. 80, 100 5. 620, 600 6. 250, 200 7. 970, 1,000 8. 330, 300 9. 450, 400 10. 210, 200 11. 100, 100 12. 710, 700
Step-by-step explanation:
Answer:
∠B=60°
Step-by-step explanation:
In this right traingle, using angle B, you have the opposite side which is 6√102, and the adjacent side which is 6√34. Using SOHCAHTOA this invlolves TOA so tangent B = OPPOSITE/ADJACENT or tan B = 6√102/6√34. Simplifying gives tan B=√3. You can use your calculator to solve for B by taking the inverse tangent of √3 or you can use the known trig ratios from the unit circle if you have already learned that to find that angle B is 60°
Step-by-step explanation:
slope formula when it's perpendicular : m1 × m = -1
Now Differentiate the quadratic function given.
d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"
= 2x - 1 .... plug in the x value
= 2 × -1 - 1 = -3.
Use this equation...
y - y1 = m(x - x1)
m = slope = derivative at x = -1
y1 = value found by subbing -1 into the original function
x1 = the x value often given.
y - 3 = 1/3 (x + 1)
= 1/3x + 1/3 + 3
y = 1/3x + 10/3.
not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.
y = 0 + 10/3 = 10/3
1/3x = 0 - 10/3
x = -10/3 / 1/3 = -10
so the point .... (-10 , 10/3)
Actually there is enough information to solve this
problem. First, let us find the total per row and per column.
(see attached pic)
P(Grade 10 | opposed) with P(opposed | Grade 10)
P(Grade 10 | opposed) = Number in Grade 10 who are opposed
/ Total number of Opposed (column)
P(Grade 10 | opposed) = 13 / 41 = 0.3171
P(opposed | Grade 10) = Number in Grade 10 who are opposed
/ Total number in Grade 10 (row)
P(opposed | Grade 10) = 13 / 32 = 0.4063
Therefore:
P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10),
hence they are dependent events.
Answer:
P(Grade 10 | opposed) < P(opposed | Grade 10)
