There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
A = 46
B = 134
C = 78
Step-by-step explanation:
Answer:
so your answer would be 60$
Step-by-step explanation:
I = P * r * t
Here, P = $600
r = 0.05 (decimal value for 5%)
t = 2 years
Part a)
The interest earned will be:
I = P * r * t
I = 600 * 0.05 * 2
I = $60
Part b)
The balance in the account will be $600 plus the interest earned or:
$600 + 60 = $660
