I’m pretty sure the answer would be A,because if her bill is $97 and it’s $0.10 every txt she sends then and she wants to spend less then $113 then if you take $113 and subtract it by 97 it gives you 16 then if you divided 16/ 0.10 then it gives you 160 so she is sending atleast 160 txt.
Answer:
i) P(X<33) = 0.9232
ii) P(X>26) = 0.001
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 30
Given that the standard deviation of the Population = 4
Let 'X' be the Normal distribution
<u>Step(ii):-</u>
i)
Given that the random variable X = 33

>0
P(X<33) = P( Z<1.5)
= 1- P(Z>1.5)
= 1 - ( 0.5 - A(1.5))
= 0.5 + 0.4232
P(X<33) = 0.9232
<u>Step(iii) :-</u>
Given that the random variable X = 26

>0
P(X>26) = P( Z>3.5)
= 0.5 - A(3.5)
= 0.5 - 0.4990
= 0.001
P(X>26) = 0.001
For discontinuity of the function:
x² - 7 x - 8 ≠ 0
x² - 8 x + x - 8 = 0
x ( x - 8 ) + ( x - 8 ) ≠ 0
( x - 8 ) ( x + 1 ) ≠ 0
The points of discontinuity are: x = - 1 and x = 8.
As for the Domain of the function:
x ∈ ( - ∞, - 1 ) ∪ ( - 1 , 8 ) ∪ ( 8, +∞ ).
Answer:
12x − 2
Step-by-step explanation:
7(x+4)+5(x−6)
Distribute:
=(7)(x) + (7)(4) + (5)(x) + (5)(−6)
=7x + 28 + 5x − 30
Combine Like Terms:
=7x + 28 + 5x − 30
=(7x+5x) + (28−30)
= 12x − 2
well, we know is 10% for the first 7500, but Dan only made 5000 of taxable income, so he's in that range of 0 - 7500, so he only gets to pay 10% of 5000.
