Answer:
2:30pm
Step-by-step explanation:
Answer:
This is easy -- it's just a list of steps. At this level, the problems are pretty simple.
Let's just do one, then I'll write out the list of steps for you.
Find the inverse of f( x ) = -( 1 / 3 )x + 1
STEP 1: Stick a "y" in for the "f(x)" guy:
y = -( 1 / 3 )x + 1
STEP 2: Switch the x and y
( because every (x, y) has a (y, x) partner! ):
x = -( 1 / 3 )y + 1
STEP 3: Solve for y:
x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3
STEP 4: Stick in the inverse notation, f^( -1 )( x )
f^( -1 )( x ) = -3x + 3
Step-by-step explanation:
Answer:
first, you need to get y on one side. So, because the x is negative it becomes positive when you switch it to the other side. 3y= 9x+5. You then need to divide all parts by 3. 3/3= 1 so thats just y. 9/3 is 3 so thats 3x. then 5/3 is a fraction that you can write as just 5/3 or 1 and 2/3. That would leave you with y= 3x + 5/3. Then x (3) is your slope. and what you add to it (5/3) is your y int.
Answer:
200 pairs of sandals
Step-by-step explanation:
Represent the sandals with x and the running shoes with y.
In a typical month:
In April
Required
The number of sandals in a typical month
<u>In a typical month:</u>
If 1 sandal costs 2.50, then x costs 2.50x
If 1 running shoe costs 4, then y costs 4y
The total is:
<u>In April:</u>
If 1 sandal costs 2.50, then 2x costs 5x ---- <em>we used 2x because the pairs is doubled </em>
If 1 running shoe costs 4, then y costs 4y
The total is:
The equations are:
Subtract
To know the mass of the sphere given the density , we first define density as
D = Mass / volume
now we have a value of density but doesn't have volume so we compute for it using the given radius 5.5 cm
V = <span>(4/3)πr^3
so
mass = D (volume)
mass = 11.34 (</span>(4/3)π(5.5)^3 )
mass = 7902.96 g <span>Hope my answer would be a great help for you.
If </span>you have more questions feel free to ask here at Brainly.
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