Question

In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?

Answer 1

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

$A=\frac{1}{2}bh$

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

$AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10$

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

$AD=AE+DE=10+4=14$

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

$A=bh$

where b is the base and h the height. Therefore, the area of this rectangle is

$A=bh=(AD)(AB)=(14)(8)=112$

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