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4 years ago

Can you guys please help me or explain to me how to do this ?

Mathematics

1 answer:

ira [324]4 years ago

7 0

12) Angle ACD= Angle ABC+ Angle CAB ====> You MAY end here
That is, Angle ACD= 132+21
            Angle ACD= 153

13) Angle ABC+ Angle BAC= Angle ACD====> You MAY end here
That is,     Angle ABC +16=143
                                   -16= -16
                Angle ABC=127

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Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago

A cylindrical tank has a height of 10 feet and a radius of 4 feet. Jane fills the tank with water at a rate of 8 cubic feet per

ki77a [65]

Given:

A cylindrical tank has a height of 10 feet.

The radius of the cylindrical tank is 4 feet.

Jane fills the tank with water at a rate of 8 cubic feet per minute.

We need to determine the time it will take for Jane to completely fill the tank without overflowing it.

Volume of the cylinder:

The volume of the cylinder can be determined using the formula,

$V=\pi r^2 h$

Substituting the values, we have;

$V=(3.14)(4)^2(10)$

$V=(3.14)(16)(10)$

$V=502.4$

Thus, the volume of the cylinder is 502.4 cubic feet.

Time taken:

The time taken can be determined using the formula,

$Time = \frac{Volume}{Rate \ of\ filling}$

Substituting the values, we have;

$Time = \frac{502.4}{8}$

$Time = 62.8$

Thus, Jane takes 62.8 minutes to completely fill the tank without overflowing it.

3 0

3 years ago

Equivalent ratio 44:99= 108:36= 33:9= 49:14=

zhuklara [117]

Answer:

44:99 = 4:9

108:36 = 3:1

33:9 = 11:3

49:14 = 7;2

hope it helps

7 0

3 years ago

How do you find the lateral area of the prism

Lina20 [59]

Hi there!

The lateral area is the area of the figures connecting the bases. We have rectangles here. We'll need to find the area of each figure and add them together to find the lateral area.

WORK:
(2.8 x 12) + (8.1 x 12) + 2(4 x 12)
33.6 + 97.2 + 96
LA = 226.8 units^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0

3 years ago

Which of these situations can be represented by the opposite of -9

Nitella [24]

The answer is B) you climb up 9 flights of stairs

7 0

3 years ago

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