Answer:
Step-by-step explanation:
20.1metres / seconds
We want to convert to metres /minutes
It is known that 60seconds=1minutes
So therefore, either we multiply 20.1metres/seconds by
60seconds/1minutes
Or
1minutes/60seconds
Multiplying with the above does not change the magnitude of the quantity because it is like we are multiplying by 1.
Since we want to cancel seconds and it is in the denominator, so to do this we need to multiply with the fraction that has the seconds as numerator.
So, we are going to multiply with 60seconds/1minutes
20.1metres/seconds ×60seconds/minutes
1206metres/minutes.
So the correct fraction is the StartFraction 60 seconds Over 1 minute, which is the third option
Not sure. has the same question
Answer:
Step-by-step explanation:
(x₁, y₁) = (19 , -4) & (x₂ ,y₂) = (17, -20)
![= \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-20-%5B-4%5D%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-20%2B4%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-16%7D%7B-2%7D%5C%5C%5C%5C%3D%208)
m = 8
Parallel lines have same slope.
Parallel slope = 8
Slope of perpendicular line = 
Perpendicular slope = 
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
