Answer:
Hello, Your answer is <em>B) Making observations</em>
<u><em>(Hope That Helps Your Answer)</em></u>
Answer:
Empirical formula is C₃H₃O.
Explanation:
Given data:
Mass of compound = 0.519 g
Mass of CO₂ = 1.24 g
Mass of H₂O = 0.255 g
Empirical formula = ?
Solution:
%age of C,H,O
C = 1.24 g/0.519 × 12/44 ×100 = 65.5%
H = 0.255 g/0.519 × 2.016/18 ×100 = 5.6%
O = 100 - (65.5+5.6)
O = 28.9%
Number of gram atoms of H = 5.6 / 1.01 = 5.5
Number of gram atoms of O = 28.9 / 16 = 1.81
Number of gram atoms of C = 65.5 / 12 = 5.5
Atomic ratio:
C : H : O
5.5/1.81 : 5.5/1.81 : 1.81/1.81
3 : 3 : 1
C : H : O = 3 : 3 : 1
Empirical formula is C₃H₃O.
Answer:
The answer to your question is D.
Explanation:
Potassium has 4 energy levels in the first level (A) has only 2 electrons,
in the second energy (B) level has 8 electrons, in the third energy level (C) also has 8 electrons and in the fourth energy level has only one electron.
Valence electrons are located in the outermost shell so Potassium has only one electron located in the shell D.
Rmm of N20 = (14X2) + 16 = 44
Percentage by mass of Nitrogen in N20 = 28/44x100 = 63.64
66x0.6634 = 43.7844g of Nitrogen in 66g of N20
Moles = Mass/Mr = 43.7844/14 = 3.13 moles
