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defon
3 years ago
5

Write an inequality to represent the situation. A cheese pizza costs at least $5.

Mathematics
2 answers:
Nady [450]3 years ago
8 0
<
-  5 dollars, the V thing sits on top of the line and 5 comes after signifying that it could be 5 dollars or more
erik [133]3 years ago
3 0

Answer: x\geq5

Step-by-step explanation:

Let variable 'x' represents the cost of a cheese pizza {in dollars}.

The given statement : "A cheese pizza costs at least $5.

"

Here, the word at least means the minimum cost of cheese pizza must be $5.

i.e. the cost of cheese pizza must be greater than or equal to $5.

Now, the inequality to represent the situation will be given by :-

x\geq5

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7 0
2 years ago
Trigonometry:
Trava [24]

A. The approximate height of the building is 100 m

B. We can use the arc length formula to obtain an approximation of BC since angle A is small.

A.

The approximate height of the building is 100 m

To find the approximate height of the building, we consider the diagram.

From the diagram, we have that using trigonometry,

tanA = BC/AB

Now

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  • BC = height of building and
  • AB = 2 km = 2000 m
<h3 /><h3>Finding the value of BC</h3>

So, making BC subject of the formua, we have

BC = ABtanA

Substituting the values of the variables into the equation, we have

BC = ABtanA

BC =2000tan0.05

BC = 2000 × 0.05

BC = 100 m

So, the approximate height of the building is 100 m

B.

We can use the arc length formula to obtain an approximation of BC since angle A is small.

<h3 /><h3>Arc Length Formula</h3>

We know that the arc length formula L = rФ where

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<h3 /><h3>The approximate height</h3>

Now BC = ABtanA

We know that Ф ≅ tanФ when Ф is small.

<h3 /><h3>The comparison</h3>

So, BC = AB × A which is the arc length formula with

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So, we can use the arc length formula to obtain an approximation of BC since angle A is small.

Learn more about approximate height of building here:

brainly.com/question/3144976

7 0
2 years ago
Which number is between 7/11 and 0.75( the 75 is repeating)
AlekseyPX

Convert 7/11 to a decimal value.

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Subtract 0.636364 to 0.757576 and divide the difference by 2.

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