The complete question is <span>∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and minor arc CA = 166, what is the measure of ∠ BEC?
the picture in the attached figure
we know that The angle formed inside of a circle by two intersecting chords is </span><span>the half-summit of the arcs that comprise it and its opposite. so </span>∠BED=(1/2)*[arc AC+arc BD]-----> (1/2)*[166+94]-----> 130° ∠BEC+∠BED=180°-----> by supplementary angles ∠BEC=180-130-----> 50° <span> the answer is </span>∠BEC=50°<span>