Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Answer:
The answer is the second answer choice
Step-by-step explanation:
In the unit circle the hypotenuse of the triangle formed is equal to radius of circle , which = 1. The point on the circle formed by the intersection of the hypotenuse is (cos q , sin q) where q is the angle between the x axis and the hypotenuse. As the hypotenuse = 1 the opposite and adjacent sides of the triangle < 1 so sin and cos of q must both be <= 1.
