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DanielleElmas [232]
3 years ago
6

When a factor x − k is raised to an odd power, the graph crosses the x-axis at x = k.

Mathematics
2 answers:
HACTEHA [7]3 years ago
5 0

Answer:

crosses at (1,0)

crosses at (-4,0)

touches at (-5,0)

Got correct on ed

Step-by-step explanation:

oksian1 [2.3K]3 years ago
4 0

Answer:

The graph of g(x) = (x - 1) (x + 4)^3(x +5)^2 crosses the x-axis at (1,0) and (-4, 0). It touches the x-axis at (-5, 0).

Step-by-step explanation:

g(x):

g(x) = (x - 1) (x - (-4))^3(x - (-5)^2.

There are three factors:

  • (x - 1), where k = 1,
  • (x - (-4)), where k = -4, and
  • (x - (-5)), where k = -5.

The first and second factors are raised to odd powers. The graph will cross the x-axis at all these two points:

  • (1, 0) as a result of the factor (x - 1),
  • (-4, 0) as a result of the factor (x - (-4)).

The third factor is raised to an even power. The graph will touch the x-axis at that point.

  • (-5, 0) as a result of the factor (x - (-5)).
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