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viva [34]
3 years ago
15

If the shorter rectangle is 1 unit long, how many units long is the longer rectangle?

Mathematics
2 answers:
Bumek [7]3 years ago
5 0
Whatever greater than 1 unit
Alla [95]3 years ago
3 0

Answer: 2 units long

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Round your answer to the nearest hundredth AC=
KatRina [158]

Answer:

AC ≈ 2.96

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos65° = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{AC}{7}

Multiply both sides by 7

7 × cos65° = AC , thus

AC ≈ 2.96 ( to the nearest hundredth )

7 0
3 years ago
What is the approximate volume of a cylinder with a radius of 3 ft and a height of 4 ft?
Lunna [17]
V≈113.1 ft³ is the answer
5 0
2 years ago
Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square
ValentinkaMS [17]

Answer:

Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = 11\frac23\ yd^2

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator,  Add that to the numerator,Then write the result on top of the denominator.

11\frac23\ yd^2 can be Rewritten as \frac{35}{3}\ yd^2

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = \frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2

Amount of fabric left with Richard = \frac56 \ yd^2

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac56

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project  = \frac{35-10}{12}= \frac{25}{12}\ yds^2

\frac{25}{12}\ yds^2 can be rewritten as 2\frac{1}{12}\ yd ^2

Hence Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

7 0
3 years ago
Can someone help me out?
Lera25 [3.4K]

Answer:

so basically

the area of the square; (5cm)^2 = 25cm^5

the area of the triangle; (4cm.5cm)/2 = 10cm^2

which means that r = √25cm^2/10cm^2 = √25/10 cm^2 or √10/25 cm^2

english is not my first language so i do not know what combined means but if u explain a little more i will try to help u

-> ok edit edit;

1cm/5in. = r

5cm => 25in.

z^2= area of a square so

25in.25in= 625 in^2

4cm => 20in.

5cm => 25in.

h.b/2 = area of a triangle so

20in.25in./2 = 250in.^2

250in.^2 + 625in.^2 = 875in.^2

so answer B

5 0
3 years ago
Read 2 more answers
Can I get your number so we can talk?
solniwko [45]

Answer:

no but you can have my gm/ail

Step-by-step explanation:

7 0
3 years ago
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