In the figure below, ∠HFG≈HKJ and ∠HF≈HK

The price of Stock A at 9 A.M. was $12.79 Since then, the price has been increasing at the rate of $0.11 each hour. At noon t

gayaneshka [121]

Answer:

2.174 hours

Step-by-step explanation:

Let the number of hours be represented as:

x

The price of Stock A at 9 A.M. was $12.79 Since then, the price has been increasing at the rate of $0.11 each hour.

$12.79 + $0.11 × x

12.79 + 0.11x

At noon the price of Stock B was $13.29 It begins to decrease at the rate of $0.12 each hour.

$13.29 - $0.12× x

13.29 - 0.12x

Equating both equations together

Stock A = Stock B

12.79 + 0.11x = 13.29 - 0.12x

Collecting like terms

0.11x + 0.12x = 13.29 - 12.79

0.23x = 0.5

x = 0.5/0.23

x = 2.1739130435 hours

x = Approximately = 2.174 hours

If the two rates continue, the number of hours that the prices of the two stocks will be the same is 2.174 hours

5 0

3 years ago

Help please thank you!

irga5000 [103]

Answer:

Step-by-step explanation:

W(-4,-10) lies on third quadrant.

M(-12,0) lies on second quadrant or can say in x axis

C(8,3) lies on first quadrant.

K(11,-5) lies on fourth quadrant.

8 0

3 years ago

If and , find . A. B. C. D.

trapecia [35]

Answer: option D. 2x^2 + (3/2)x - 5

Explanation:

1) polynomials given:

f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3

2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

3) x/2 - 2 + 2x^2 + x - 3

4) Combine like terms:

a) terms with x^2: you only have 2x^2, so it is not combined with other term.

b) terms with x: x/2 + x

that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x

c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.

4 0

3 years ago

A store sells flower arrangements at a cost of $28 each. Which statements are true regarding the price of the arrangements? Chec

Maru [420]

Let's check each case to determine the solution to the problem.

we know that

The cost of each flower arrangements is $\$28$