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Marrrta [24]
3 years ago
12

[ 1 ] check whether -3 and 3 are the zeroes of the polynomial x² - 9.

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

<h3>#1</h3>
  • x² - 9 = 0
  • x² = 9
  • x = ± √9
  • x = ± 3

Yes, -3 and 3 are zeroes of this polynomial

<h3>#2</h3>

<em>See attached graphs</em>

Zero's of a polynomial are the intersection of the graph with the x-axis.

They include coordinates as (x, 0), so the x-coordinates are zero's.

The attached shows the zero's.

<h3>#3</h3>

<em>See attached graphs</em>

Zero's of each polynomial are reflected in the graphs.

  • () y = x² - x - 6 has zeros x = -2 and x = 3
  • (ii) y = 6 - x - x² has zero's x = -3, x = 2

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Step-by-step explanation:

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What’s the vertex form of F(x)=x^2+2x-3
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Answer:

\large\boxed{f(x)=(x+1)^2-4}

Step-by-step explanation:

\text{The vertex form of a quadratic equation}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-\text{vertex}\\=====================================

\bold{METHOD\ 1:}\\\\\text{convert to the perfect square}\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\f(x)=x^2+2x-3=\underbrace{x^2+2(x)(1)+1^2}_{(*)}-1^2-3\\\\f(x)=(x+1)^2-4\\==============================

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4 0
3 years ago
Please help me answer 16 please
amm1812

Answer:

SSS

Step-by-step explanation:

I can identify that these triangles are congruent by using the SSS (Side, Side, Side) postulate theorem. I know this because first, second, and home triangle share the same side as the third, second, and home triangle, meaning they are congruent, so are the other sides of the angle since the question states they are congruent.

5 0
3 years ago
A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about
Radda [10]

Answer:

f(2)=5

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Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

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4 0
2 years ago
I need the answer and explanation to how you get the answer please, please, I’m giving 30 points...
12345 [234]
Step 1 = 3.9 × 0.5 + 4 5/6 ÷ 3 3/7
Step 2 = 3.9 × 0.5 + 29/6 ÷ 24/7
Step 3 = 4.4 + 29/6 × 24/7
Step 4 = 4.4 + 29/1 × 4/7
Step 5 = 4.4 + 111/7
Step 6 =44/10 + 111/7


Step one : Write the problem
Step two : Change the mixed numbers to improper fractions
Step three : Multiplication and Division should be done first. Then simplify.
Step four : Change the division to multiplication and multiply.
Step 6 : Add the remaining fractions


Sorry i didn't know which one so i did the first one. Hope it helps you.
8 0
3 years ago
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