Any image??????????...........
Complete the square of y^2 + 10y to answer this question.
x=y^2 + 10y + 22 becomes x = <em>y^2 + 10y + 100</em> - 100 + 22, or
x = (y+10)^2 - 78
Comparing this result to the generic form x = a(y-k)^2 + h, we see that
h = -78 and k = -10.
Then the vertex of this parabola is at (-78, -10).
The answer is 8.90g, hope this helps.
Answer:
This is Pythagorean theorem
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
the qoustion is not correct