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Fed [463]
3 years ago
13

Triangle QRS is plotted in Quadrant I. After a 180° rotation about the origin, which quadrant would its image be? quadrant I qua

drant II quadrant III quadrant IV

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0
Triangle QRS is plotted in Quadrant I. After a 180° rotation about the origin, which quadrant would its image be? quadrant III
Pavlova-9 [17]3 years ago
8 0

Answer with explanation:

The Vertices of Triangle QRS , is not given.

Coordinates of vertices of Preimage, will be Positive,that is, (x,y),x→Positive, y→Positive

while coordinates of vertices of Image will be Negative that is

x→Negative, y→Negative.

≡If we Rotate the Triangle QRS, which is in Quadrant I ,whatever the coordinates of it's vertices be, if rotated ,either in, 180°, Clockwise or Anticlockwise Direction, it will be in Quadrant III.

⇒Option C

→→ Quadrant III

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Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

<u>Use </u><u>distance</u><u> formula</u><u>.</u>

d =  \sqrt{ {(x2 - x1)}^{2} +  {(y2 - y1)}^{2}  }

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d =  \sqrt{ {( - 4 + 4)}^{2}  + (  { - 10  + 4)}^{2} }

~ Simplify it.

d =  \sqrt{ {0}^{2} + ( { - 6)}^{2}  }

d =  \sqrt{36}

Therefore, distance between the points is 6 units.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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