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vlada-n [284]
2 years ago
10

Julian saved $180 to spend on clothing. If pants cost $15 each and t shirts cost $9 each, what is the greatest number of pants t

hat's julian can purchase?
Mathematics
1 answer:
Tcecarenko [31]2 years ago
7 0
12? 180$ divided by 15$
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mamaluj [8]

Answer:

4π

Step-by-step explanation:

4x² + 9y² = 36

Divide all  through by 9

4/9x² + ²y² = 44

\int\limits^3_0 {\pi y^{2} } \, dx

\int\limits^3_0 {4-\frac{4}{9} }x^{2}  \, dx

4 0
2 years ago
In the figure, GK bisects FGH
bija089 [108]

Answer:

w = 7

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

104 = 2*(7w + 3) (substitution)

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\frac{104}{2} = \frac{2*(7w + 3)}{2}

52 = 7w + 3

Subtract 3 from each side

52 - 3 = 7w + 3 - 3

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Divide both sides by 7

\frac{49}{7} = \frac{7w}{7}

7 = w

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8 0
3 years ago
15 is 10 percent of what number
aksik [14]
Your answer is 1.5 if you multiply 15 by 10% you get 1.5 and if you ivide 1.5 by 10% you get 15 so you can find your answer and check it
hope this helps have a nice day.
4 0
2 years ago
Li Na is going to plant 6363 63 tomato plants and 8181 81 rhubarb plants. Li Na would like to plant the plants in rows where eac
Whitepunk [10]

Answer: The greatest number of rows Li Na can plant is 9.


Step-by-step explanation:

Given: Li Na is going to plant 63 tomato plants and 81 rhubarb plants.

Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.

To find the greatest number of rows Li Na can plant, we need to find the GCF of 63 and 81.

Since , 63=7\times9\ and\ 81=8\times9

Clearly, GCF(63,81)=9

Therefore, the greatest number of rows Li Na can plant is 9.

6 0
2 years ago
It is given that quadrilateral ABCD is a kite. We know
NemiM [27]

Answer:

Kite

Perpendicular

Reflexive

HL

Step-by-step explanation: Just did it on edg 2021.

3 0
2 years ago
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