3 years ago

Please quickly help me!!

Mathematics

1 answer:

Ainat [17]3 years ago

4 0

Look at the picture.

Answer:

$\angle ADB\cong\angle ACB\\\\\angle DAC\cong\angle DBC$

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Triangle ABC is similar to triangle DEF. The length of BC is 21cm. The length of DE is 10 cm. The length of EF is 14 cm. What is

Anarel [89]

It's a similar triangle so the ratios of corresponding sides should be equal which means

BC/EF = AB/DE
21/14 = AB/10
AB = 21/14 * 10 = 15 cm

8 0

3 years ago

Read 2 more answers

Let x be the amount of time (in hours) the wait is to get a table at a restaurant. Suppose the cdf is represented by f(x)=⎧⎩⎨⎪⎪⎪

sattari [20]

Option a is correct. The calculated answer is 0.150

<h3>How to get the value using the cdf</h3>

In order to get P(0.5 ≤ X ≤ 1.5).

This can be rewritten as

p = 0.5

and P = 1.5

We have the equation as

$\frac{1}{16} x^{2}$

This would be written as

1.5²/16 - 0.5²/16

= 0.1406 - 0.015625

= 0.124975

This is approximately 0.1250

Read more on cdf here:

brainly.com/question/19884447

#SPJ1

<h3>complete question</h3>

Use the cdf to determine P(0.5 ≤ X ≤ 1.5).

a) 0.1250

b) 0.0339

c) 0.1406

d) 0.0677

e) 0.8750

f) None of the above

4 0

2 years ago

Please help! question is in the pic

steposvetlana [31]

Answer: 2 + 1 = 3 2 x 1 =2

Step-by-step explanation: + 7 = 7

5 0

3 years ago

If 3(x+2)=5(x-8) what is the value of x+2?<br><br>A. 23<br>B.25<br>C.40<br>D.46

lorasvet [3.4K]

3*x

3*2

3x+6

5*x

5*-8

5x-40

Story short the answer is 25

3 0

3 years ago

Read 2 more answers

A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal

mars1129 [50]

Answer:

$t=5.0days$

Step-by-step explanation:

Using the formula for the exponential decay that is $N=N_{0}e^{-kt}$ , we have N= $\frac{1}{2}{\times}46=23$ , $N_{0}=46$ and k=0.1374.

Thus, $N=N_{0}e^{-kt}$ becomes

$23=46{\times}e^{-0.1374t}$

$\frac{23}{46}=e^{-0.1374t}$

$\frac{1}{2}=e^{-0.1374t}$

Taking log on both sides, we get

$ln(\frac{1}{2})={-0.1374t}$

$t=\frac{ln\frac{1}{2}}{-0.1}$

$t=\frac{-0.6931}{-0.1374}$

$t=5.0days$

4 0

3 years ago