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vovangra [49]
2 years ago
14

Find the functional values g (-3), g (0), and g (5) for the compound function.

Mathematics
2 answers:
Zinaida [17]2 years ago
5 0

Answer:

g(-3)=7

g(0)=7

g(5)=\dfrac15

Step-by-step explanation:

g(x) =\begin{cases}7 & \text{if } x \leq 0 \\ \\\dfrac{1}{x} & \text{if } x > 0\end{cases}

This means:

  • when x is equal to zero or less than zero, g(x) will always be 7.
  • when x is more than zero, g(x) is \frac{1}{x}

\implies g(-3)=7

\implies g(0)=7

\implies g(5)=\dfrac15

Studentka2010 [4]2 years ago
5 0

\sf\f(x)=\grey{\begin{cases}\rm 7\quad ,x\geqslant 0\\ \rm \dfrac{1}{x}\quad ,x>0\end{cases}}

So

  • -3,0 ≤0
  • 5>0

Hence

  • g(-3)=g(0)=7
  • g(5)=1/5
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Which equation has a graph that is a parabola with a vertex at (–2, 0)?
MaRussiya [10]

Answer:

The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.

If the function has a positive leading coefficient, the vertex corresponds to the minimum value.

If it has a negative leading coefficient,  the vertex corresponds to the maximum valuevalue

If the vertex is located at

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The possibilities are

y =  (x-2)^2

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Since the problem tells us the answer, we adopt the positive values

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Help me pls!!!!!!!!!
Dominik [7]

Answer:

x^2+18=-9x : x = -3, x = -6

Step-by-step explanation:

x^2+18=-9x

Add 9x to both sides:

x^2+18+9x=-9x+9x

Simplify:

x^2+9x+18=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

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x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6

The solution to the quadratic equation are:

x=-3,\:x=-6

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0
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