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3 years ago

Find the value of each variable that ensures that each equilateral is a parallelogram

Mathematics

1 answer:

puteri [66]3 years ago

8 0

Opposite sides are equal in a parallelogram.

$3a-12 = \frac{1}{2}a-7$

$\frac{5}{2}a = 5$

$a = 2$

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What is the greatest common factor of 60 and 72

Tcecarenko [31]

Well there both even numbers so the gcf factor would have to be even also

60 = 1,2,3,4,5,6,10,12,15,20,30,60

72 = 1,2,3,4,6,8,9,12,18,24,36,72

The Gcf would be 12

3 0

3 years ago

Which list is in order from least to greatest? (PS you will see it is more organized once you click on the question)

Studentka2010 [4]

I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times

4 0

3 years ago

Write an equation for each situation, Then solve your equation.

Rus_ich [418]

The answer is 1because a number is multiple by 20 then 200 and multiple by 3 -7=1

7 0

3 years ago

)if there are 8 parts in a product and they are each at 6 sigma with a 1.5 shift, determine the ppm for the product

Maru [420]

Answer:

ppm value = 0.000027 parts per million

Step-by-step explanation:

Given:

number of parts(n) = 8

From table: percent conformance in six sigma = 0.9999966

Using the formula of ppm value in terms of percent conformance and number of parts:

$ppm\,value = ( 1 -( \frac{percent\,conformance}{100} )^n )$

Plugging in the values:

$ppm\,value = (1 - (\frac{0.9999966}{100} )^8 )$

$ppm\,value = ( 1- 0.999972)\\$

$ppm\,value = 0.000027\,parts\,per\,million$

6 0

3 years ago

A company makes gift boxes in different sizes following the pattern shown below. What is the volume of the fourth gift box to th

AVprozaik [17]

The volume of the fourth box is of 410.1 cubic inches.

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The volume of a rectangular prism is given by the base area multiplied by the height, that is:

$V = A_bh$

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For the first three boxes, the height is constant at 9 inches.
At the base, the edge length is multiplied by 1.5 each time, as $\frac{4.5}{3} = \frac{3}{2} = 1.5$ , thus, for the fourth box, the edge length, in inches, will be of $4.5 \times 1.5 = 6.75$

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Square base, of length 6.75 inches, thus:

$A_b = 6.75^2 = 45.5625$

Height of 9 inches, thus $h = 9$ and:

$V = A_bh = 45.5625(9) = 410.1$

The volume of the fourth gift box will be of 410.1 cubic inches.

A similar problem is given at brainly.com/question/23756783

4 0

3 years ago