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pickupchik [31]
3 years ago
12

Solve for x. really beed help before my final!!!!​

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

√19 or 4.36

Step-by-step explanation:

Since one leg is missing, you need to use Pythagorean theorem for this.

The hypotenuse is known so,

c² - a² = b²

c = 10

a = 9

b = ?

10² - 9² = b²

100 - 81 = b²

19 = b²

b = √19

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I’d ABCD is dilated by a scale factor of 2 about point E, which of the following is true about line segment E’F’
PilotLPTM [1.2K]

Answer:

Line Segment EF passes through the center of the dilatation

Step-by-step explanation:

I just know...

3 0
3 years ago
Find the slope-intercept form of a line that goes through the point (-1,3) and is parallel to -x+3y=12
Aliun [14]
First, I would simplify the given equation to find the slope of the parallel line as it will be the same for the line we are looking for.
3y=x+12
y=(x/3)+4

Slope= 1/3

Our equation now looks close, but we need the intercept.
y=(x/3)+B

Plug in the given point to find the intercept.
3=(-1/3)+B
4/3=B

Plug all the known values into the equation to complete the slope-intercept form.
y=(x/3)+4/3
6 0
3 years ago
11-3x-7-3x=7 <br> x=?<br> PLEASE HELP I REALLY NEED IT
erastova [34]

Answer:

x=-1/2

Step-by-step explanation:

-6x+4=7

-6x=7-4

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x=3/-6

x=-1/2

3 0
4 years ago
Consider the series 4 + 12 + 36 ... Find the sum of the first 9 terms.​
jeyben [28]

Answer:

39364

Step-by-step explanation:

You can simplify the equation to make 4(1+3+9...) The nth term is therefore 3^{n-1} so u can substitute that into the equation so 4(3^{n-1}+ 3^{n}  + 3^{n+1}..). This would simplify to 4(3^0 +3+3^2+3^3+3^4+3^5+3^6+3^7+3^8). By simplifying this, you can make it so 4(2^2+6^2+18^2+42^2+81^2) = 4(4+36+324+2916+6561) =39364

3 0
2 years ago
A counselor at a middle school must create an arranged schedule of elective classes for the last 2 periods of the day for all of
Vikki [24]

Solution

The counselor has 12 electives courses (e.g. art, band, PE, etc.) to choose from and must select 2 ordered classes for each 6th grade student.

Let S be the sample space.

Then, n(S) = 12C2 = (12 x 11) ÷ (2 x 1 ) =  132 ÷ 2 =  66

Then, n(S) = 12C2 = (12 x 11) ÷ (2 x 1 ) =  132 ÷ 2 =  66

Sixty six (66) ways can the counselor arrange the last 2 periods of the day for the 6th grade students

7 0
3 years ago
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