Answer:
a. 45 π
b. 12 π
c. 16 π
Step-by-step explanation:
a.
If a 3×5 rectangle is revolved about one of its sides of length 5 to create a solid of revolution, we can see a cilinder with:
Radius: 3
Height: 5
Then the volume of the cylinder is:
V=π*r^{2} *h= π*(3)^{2} *(5) = π*(9)*(5)=45 π
b. If a 3-4-5 right triangle is revolved about a leg of length 4 to create a solid of revolution. We can see a cone with:
Radius: 3
Height: 4
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(3)^{2} *(4) = (1/3)*π*(9)*(4)=12 π
c. We can answer this item using the past (b. item) and solving for the other leg revolution (3):
Then we will have:
Radius: 4
Height: 3
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(4)^{2} *(3) = (1/3)*π*(16)*(3)=16 π
Answer:
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Answer:
<em><u>A:</u></em>
<em><u>Square</u></em>
<em><u>Rectangle</u></em>
<em><u>Parallelogram</u></em>
<em><u>Quadrilateral</u></em>
<em><u>Rhombus</u></em>
<em><u></u></em>
<em><u></u></em>
Step-by-step explanation:
All sides and angles are equal so it is a square
All angles are 90 degrees so it is a rectangle (eliminate C)
Opposing angles and side lengths are congruent so it is a parallelogram (eliminate D)
It has 4 sides so it is a quadrilateral (eliminate B)
Since all of the other answers are eliminated you don't necessarily need to prove that is is a rhombus, but it is good practice.
Opposing sides are congruent so it is a rhombus.
Answer:
30
Step-by-step explanation:
