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3 years ago

Which theorem can be used to prove that the triangles in the figure below are congruent?

Mathematics

1 answer:

Minchanka [31]3 years ago

6 0

Answer:

There are 5 theorem to prove the triangles are congruent. They are:

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URGENT GEOMETRY!!

Darina [25.2K]

Answer: 140 degrees

A straight line is 180 degrees. Since we know one of the angles in the line is 40, we just subtract 40 from 180. So, the measure of angle 1 plus the measure of angle 2 is 140 degrees.

6 0

2 years ago

A rectangular prism has a length of 12in, a height of 5in, and a width of 8in. What is its volume, in cubic in?

cupoosta [38]

Answer: The volume is 480 in^3

Step-by-step explanation:

v= lwh

v= 12 * 5 * 8

v= 480 in^3

3 0

3 years ago

Read 2 more answers

13) (3 + 7v2)(3 – 7v2)

Dovator [93]

Answer:

the answer to this problem is

9 - 21v^2 + 21v^2 - 49v^4

9 - 49v^4

Step-by-step explanation:

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3 years ago

Hello Please help me.

olga55 [171]

Answer:

Step-by-step explanation:

1) D

2) B

3) no solution

y ≤ 0.5x - 4 is area C including the red line

y ≥ 0.5x + 5 is area A including the blue line

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3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

3 years ago