The area of a rectangle is obtained through the equation,
A = L x W
The width of the yard is 4 ft less than the length and may be expressed as L - 4. Length may be solved through the following steps,
A = (L)(L-4) ; 96 = L(L - 4) ; L = 12 ft
The length and width are 12 ft and 8 ft, respectively. Perimeter may be solved through the equation,
P = 2 x (L + W)
Substituting the values of L and W
P = 2 x ( 12 ft + 8 ft) = 40 ft
Therefore, the perimeter of the yard is 40 ft.
Answer:
Step-by-step explanation:
∠CAB = 33 {alternate interior angles}
5x = 33 + 2x { exterior angle equals sum of opposite interior angles}
5x - 2x = 33
3x = 33
x = 33/3
x = 11
∠B = 2x = 2* 11 = 22
∠ECB = 5x = 5*11 = 55
Answer:
Step-by-step explanation:
21 hits / 45 at bats
7/15
If the regular soccer goal was 24 ft wide and the kid soccer goal was 6 ft wide 6x4=24 so if you would do the same thing to the height the kid soccer goal would be 2 ft tall
No, because the sum of any of the sides must be greater than all sides. 5.6 +4.0=9.6 which is less than 10.6, meaning that it is impossible to create a triangle with those lengths.
