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Tom [10]
2 years ago
12

Please helppp i need to finish it

Mathematics
1 answer:
horsena [70]2 years ago
4 0
X =12x yeah hope helps
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The variable Z is directly proportional to X. When X is 12, Z has the value 228. What is the value of Z when X = 18
Kisachek [45]
Here, z = kx

k = z/x
k = 228/12
k = 19

So, when x = 18, 
z = 19 * 18
z = 342

In short, Your Answer would be: 342

Hope this helps!
8 0
3 years ago
2 and 3 are<br> angles.<br> complementary<br> vertical<br> congruent<br> supplementary
Lapatulllka [165]

Answer:

supplementary

Step-by-step explanation:

Angles 2 and 3 form a straight line.  Straight lines are supplementary

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3 years ago
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The time needed for all college students to complete a certain paper-and-pencil maze follows a normal distribution with a popula
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Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
Evaluate the expression 2x2 - yl yl + 3xº for x = 4 and y = 7​
Bond [772]

Answer:

replace the given values of x and y

Step-by-step explanation:

hope it helped!!!

6 0
3 years ago
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