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3 years ago

9

Write the point-slope form of the equation of the line with a slope of - 2 and an x-intercept of - 1. Include your work in your

final answer.

1 answer:

kodGreya [7K]3 years ago

7 0

Use y = mx + b.

the m represents the slope, b represents the Y intercept.

y = -2x - 1

Hope this helps :D

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Alexis bought a pyramid-like paperweight for her teacher. The paperweight has a volume of 200 cm3 and a density of 1.5 grams per

Nikolay [14]

Answer:

The density is equal to the weight divided by the volume:

$\rho=\dfrac{W}{V}$

The paperweight weights 300 grams.

Step-by-step explanation:

The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.

The density is equal to the weight divided by the volume:

$\rho=\dfrac{W}{V}$

We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.

We can use the formula of the density to calculate the weight:

$\rho=\dfrac{W}{V}\\\\\\W=\rho\cdot V=1.5\;\dfrac{g}{cm^3}\,\cdot\;200\; cm^3\\\\\\W=300\;g$

The paperweight weights 300 grams.

7 0

2 years ago

Solve x^2- 8x = 20 by completing the square. Which is the solution set of the equation?

yanalaym [24]

The solution is -2 and 10

5 0

3 years ago

What is the solution for x in the equation?<br><br> 10x − 4.5 + 3x = 12x − 1.1

Aleksandr [31]

Answer:in first part of equation add 10x and 3x (like terms)

13x-4.5=12x-1.1

move all terms containing x to left side of equation

13x-4.5-12x= -1.1

x-4.5= -1.1

Subtract 4.5 from both sides

x=3.4

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean

Maksim231197 [3]

The correct option is: a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is: $z= \frac{X-\mu}{\sigma}$

Newborn males have weights with a mean $(\mu)$ of 3272.8 g and a standard deviation $(\sigma)$ of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69$

According to the normal distribution table, $P(z=-2.69)=0.0036 = 0.36\%$

Now, newborn females have weights with a mean $(\mu)$ of 3037.1 g and a standard deviation $(\sigma)$ of 706.3 g.

So, the z-score for the newborn female who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18$

According to the normal distribution table, $P(z=-2.18)=0.0146 = 1.46\%$

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>, so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0

2 years ago

Elena-2011 [213]

Answer:

<h2>9.2</h2>

Step-by-step explanation:

The distance formula is:

$d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2$

-4 - 2 = -6 squared = 36

4 - -3 = 7 squared = 49

36 + 49 = 85

$\sqrt{85} =$ about 9.2

I'm always happy to help :)

4 0

3 years ago