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igomit [66]
3 years ago
6

a paper factory makes 8423 sheets of paper in 45v minutes. how many sheets of paper does the factory makes in 1 minute

Mathematics
2 answers:
sergeinik [125]3 years ago
7 0
187 I used cross multiplication to solve the problem
rosijanka [135]3 years ago
3 0
8423 / 45v

187.1777 = v

187 papers per minute.
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Solve for x in simplest form. 9=8/5(x+5) ​
Natasha_Volkova [10]

Answer:

5/8 =x

Step-by-step explanation:

9=8/5(x+5) ​

Multiply each side by 5

5* 9=5*8/5(x+5) ​

45 = 8(x+5)

Distribute

45 = 8x+40

Subtract 40 from each side

45-40 = 8x+40-40

5 = 8x

Divide each side by 8

5/8 = 8x/8

5/8 =x

3 0
3 years ago
Area of the bounded curves y=x^2, y=√(7+x)
N76 [4]

Answer:

\displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:                                                               \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                       \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

U-Substitution

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \left \{ {{y = x^2} \atop {y = \sqrt{7 + x}}} \right.

<u>Step 2: Identify</u>

<em>Graph the systems of equations - see attachment.</em>

Top Function:  \displaystyle y = \sqrt{7 + x}

Bottom Function:  \displaystyle y = x^2

Bounds of Integration: [-1.529, 1.718]

<u>Step 3: Integrate Pt. 1</u>

  1. Substitute in variables [Area of a Region Formula]:                                   \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx
  2. [Integral] Rewrite [Integration Property - Addition/Subtraction]:               \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \int\limits^{1.718}_{-1.529} {x^2} \, dx
  3. [Right Integral] Integration Rule [Reverse Power Rule]:                             \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - \frac{x^3}{3} \bigg| \limits^{1.718}_{-1.529}
  4. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{1.718}_{-1.529} {\sqrt{7 + x}} \, dx - 2.88176

<u>Step 4: Integrate Pt. 2</u>

<em>Identify variables for u-substitution.</em>

  1. Set <em>u</em>:                                                                                                             \displaystyle u = 7 + x
  2. [<em>u</em>] Basic Power Rule [Derivative Rule - Addition/Subtraction]:                 \displaystyle du = dx
  3. [Limits] Switch:                                                                                               \displaystyle \left \{ {{x = 1.718 ,\ u = 7 + 1.718 = 8.718} \atop {x = -1.529 ,\ u = 7 - 1.529 = 5.471}} \right.

<u>Step 5: Integrate Pt. 3</u>

  1. [Integral] U-Substitution:                                                                               \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx= \int\limits^{8.718}_{5.471} {\sqrt{u}} \, du - 2.88176
  2. [Integral] Integration Rule [Reverse Power Rule]:                                       \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = \frac{2x^\Big{\frac{3}{2}}}{3} \bigg| \limits^{8.718}_{5.471} - 2.88176
  3. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 8.62949 - 2.88176
  4. Simplify:                                                                                                         \displaystyle \int\limits^{1.718}_{-1.529} {\sqrt{7 + x} - x^2} \, dx = 5.74773

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
3 years ago
Ahmad lost 50 dollars from his pocket.<br><br>Write a signed number to represent this change.
IRINA_888 [86]

Answer:

-50

Step-by-step explanation:

it could be X-50=?

8 0
3 years ago
You have a jar of marbles with 7 red, 12 blue, 6 yellow, and 9 white. What is the probability of selecting a marble that is not
Schach [20]

Answer:

The probability of selecting a marble that is not red, replacing it and then one that  is white is 0.2102

Step-by-step explanation:

Number of red marbles = 7

Number of blue marbles = 12

Number of yellow marbles = 6

Number of white marbles = 9

Total marbles = 7+12+6+9=34

Probability of selecting red marble =\frac{7}{34}

Probability of selecting no red marble = 1-\frac{7}{34}=\frac{27}{34}

Now replacing it one marble is drawn again

So, Probability of getting white marble =\frac{9}{34}

So,the probability of selecting a marble that is not red, replacing it and then one that  is white =\frac{27}{34} \times \frac{9}{34}=0.2102

Hence the probability of selecting a marble that is not red, replacing it and then one that  is white is 0.2102

3 0
3 years ago
Find the product. (3.5(-3.4)
lora16 [44]

Answer:

-11.9

Step-by-step explanation:

3 0
3 years ago
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