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alina1380 [7]
3 years ago
8

Step : You should now have four terms Directions: Factor each polynomial. 2x2 + 17x + 21

Mathematics
1 answer:
solmaris [256]3 years ago
6 0

Answer:

(x + 7)(2x + 3)

Step-by-step explanation:

Given

2x² + 17x + 21

Consider the factors of the product of the x² term and the constant which sum to give the coefficient of the x- term.

product = 2 × 21 = 42 and sum = + 17

The factors are + 14 and + 3

Use these factors to split the x- term

2x² + 14x + 3x + 21 ( factor the first/second and third/fourth terms )

= 2x(x + 7) + 3(x + 7) ← factor out (x + 7) from each term

= (x + 7)(2x + 3) ← in factored form

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Step-by-step explanation:

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(Just because I'm a high schooler doesn't mean that I don't know this I take AP and IB classes)

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E 0.923

Step-by-step explanation:

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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

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