Answer:
16(x-2)(x+2)
Step-by-step explanation:
Remember that

so

(a+ b)^2 = a^2 + 2ab + b^2
1. x^2 + 2x*9i + (9i)^2 = x^2 + 18xi - 81
2. x^2 + 2x*(3+5i)+ (3+5i)^2 = x^2 + 6x + 10xi+ 9+30i-25 = x^2 - 16 + 30i + 6x + 10xi
Answer:
1)
2) 
Step-by-step explanation:
Please ignore the squiggle in the middle of the page.
Please mark brainliest when you’re able :)
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)