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Montano1993 [528]
3 years ago
13

Brian’s kite is flying above a field at the end of 65m of string. If the angle of elevation to the kite measures 70; how high is

the kite above Brian’s head?
Mathematics
1 answer:
REY [17]3 years ago
7 0
If the height is h, then h/65=sin70, so h=65sin70=61.08m approx.
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Plz help no links :)
Ilya [14]

Answer:

C) f(x) = 6.25x + 3

Step-by-step explanation:

In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be

f(x) = 6.25x + 3

We can input the # of candies for x and see that it provides the exact results every time as seen in the table.

f(x) = 6.25(1) + 3 = 9.25

f(x) = 6.25(2) + 3 = 15.50

f(x) = 6.25(3) + 3 = 21.75

f(x) = 6.25(4) + 3 = 28

4 0
3 years ago
Please help!! :) :) ;)
otez555 [7]
Complementary angles are angles who sum to 90 degrees. So, since one angle is 13 degrees, naturally the other must equal 77. Good luck! c:
8 0
3 years ago
Complete the equation for the standard form of the line that has an x-intercept of –4 and a y-intercept of 3
Kazeer [188]

Answer:

The equation for the standard form of the line will be:

  • 3x + (-4y) = -12

Step-by-step explanation:

Given

  • x-intercept = –4
  • y-intercept = 3

The equation of a line in standard form

  • Ax + By = C

where A is a positive integer and B, C are integers

We know the equation of a line in  slope-intercept form

y = mx+b

where m is the slope and b the y-intercept

To calculate the slope, use the gradient formula

m = y₂-y₁ / x₂-x₁

let  

(x₁, y₁) = (-4, 0)             ∵ x-intercept = (-4, 0)

(x₂, y₂) = (0, 3)              ∵ y-intercept = (0, 3)

m = y₂-y₁ / x₂-x₁

    = (3 - 0) / (0 - (-4))

    = 3 / 4

Thus, the equation in slope-intercept form:

y = mx+b

y = 3/4x + 3

  • Writing in standard form

Multiply y = 3/4x + 3 by 4

4y = 3x + 12

3x-4y = -12

3x + (-4y) = -12

Thus, the equation for the standard form of the line will be:

  • 3x + (-4y) = -12

7 0
3 years ago
Which of the following expressions is equal to 1 divided by 16
Ber [7]
The correct answer is:  [A]:  " (\frac{1}{2})⁴ " .
_______________________________________________

Note:  (\frac{1}{2})⁴  = \frac{1^{4} }{2^{4} } ;

                                                = \frac{1*1*1*1}{2*2*2*2} ;

                                                = \frac{1}{16} .
_______________________________________________________

Consider "Choice [B]" :  "(\frac{1}{2})⁴ " ;

Note:  (\frac{1}{4})⁴ =  \frac{1^{4} }{4^{4} } ;

                                                = \frac{1*1*1*1}{4*4*4*4} ;

                                                = \frac{1}{256} .

Note that:  "\frac{1}{256}" \neq "\frac{1}{16}" .
__________________________________________________________

Consider "Choice [C]" :  "(\frac{1}{8})² " ; 

Note:  (\frac{1}{8})²  = \frac{1^{2} }{8^{2} } ;

                                                = \frac{1*1}{8*8} ;

                                                = \frac{1}{64} .

Note that:  "\frac{1}{64}" \neq "\frac{1}{16}" .
__________________________________________________________
     →  As such, the only correct answer choice is:
__________________________________________________________
Answer choice:   [A]:  " (\frac{1}{2})⁴ " .
__________________________________________________________
6 0
3 years ago
I need help with this question
Murrr4er [49]

The number of cows is given by

14\cdot 2^{\frac{y}{5}}

So, after k years, the number of cows will be

14\cdot 2^{\frac{y+k}{5}}

We want this number to be twice as much as the original:

14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})

First of all, we can cancel 14 from both sides:

2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}

Finally, on the right hand side, we can use the exponent rule

a^b\cdot a^c=a^{b+c}

to get

2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}

To solve this equation, we must impose that the two exponents are the same:

\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}

And clearly this is true if and only if k=5. So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0
3 years ago
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