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zubka84 [21]
2 years ago
13

On Friday it was 32 degrees at 6am and the temperature rose 3 degrees per hour for several hours. How many hours did it take the

temperature to reach 53 degrees?
Mathematics
1 answer:
sertanlavr [38]2 years ago
4 0
At 1 pm is was 53 degrees
It took 7 hours
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Describe how you would graph a figure that is translated by (x - 4,4+2).
atroni [7]

Answer:

see explanation

Step-by-step explanation:

Given the translation rule

(x, y ) → (x - 4, y + 2 )

This means subtract 4 from the original x- coordinate and add 2 to the original y- coordinate, that is

a point (4 , - 4 ) → (4 - 4, - 4 + 2 ) → (0, - 2 )

8 0
3 years ago
The table represents a linear function. Which is the slope of the function?
Galina-37 [17]

From the table we have the points (-4, -2) and (-2, -10).

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute:

m=\dfrac{-10-(-2)}{-2-(-4)}=\dfrac{-10+2}{-2+4}=\dfrac{-8}{2}=-4

<h3>Answer: The slope = -4.</h3>
7 0
3 years ago
Read 2 more answers
What is the area of the hexagon below?
sergejj [24]

Answer:

14m^2

Step-by-step explanation:

To find the area of this hexagon, you should separate this shape into 2 other shapes.

You can see that there is a parallelogram, and a rectangle shape within this hexagon, so you can find the area of these 2 shapes and later on, just add it.

The area of this rectangle is...

width✖️height: 6✖️2=12

The area of this parallologram is...

base✖️height: 6✖️2=12

12+12=14m^2

6 0
2 years ago
How can you tell a graph is proportional
Flura [38]

Answer:

If the line passes through the orgin

Step-by-step explanation:

6 0
2 years ago
How to bring the polynomial to the standard form p(x) x^2-2x+4) (x^2+2x+4) ​
saveliy_v [14]
<h3>Solution:</h3>

\rightarrow\sf((p(x) {x}^{2}  + 2x + 4)( {x}^{2}  + 2x + 4)) \\  = \sf  {ax}^{2}  + bx + c \\  = \sf(p(x) {x}^{2}  {x}^{2}  + p(x) {x}^{2} (2x) + p(x) {x}^{2}  \times 4 + 2x \times  {x}^{2}  + 2x(2x) + 2x \times 4 +  {4x}^{2}  + 4(2x) + 4 \times 4) \\  = \sf( {x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16) \\   \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

<h3>Answer:</h3>

\large\boxed{\sf{\red{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

\color{red}{==========================}

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

✍︎ꕥᴋɪᴍ ᴀʀᴀꕥ

5 0
2 years ago
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