Solve each system by substitution <br> x^2 − 14x + 49 = 4?

With solving and it’s better to edit the photo and send it

Daniel [21]

Step-by-step explanation:

please mark me as brainlest

5 0

2 years ago

Which figure has both lines of symmetry and symmetry and rotation symmetry?

Sedaia [141]

Answer:

Pentagon

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Kameron's unicycle wheel has a spoke length of 16 inches.

Alexeev081 [22]

Answer:

301.44 inches

Step-by-step explanation:

The spoke is from the center of the wheel to the edge, so its length is the radius, or 16 inches.

You want to find the distance that one rotation will take you, so you need the wheel's circumference.

Circumference = 2πr

2 x 3.14 x 16 = 100.48

100.48 inches is the distance of only 1 full rotation, so you just need to multiply 100.48 by 3 to get the distance of 3 rotations.

100.48 x 3 = 301.44

3 0

3 years ago

Quiz! Help!

Evgen [1.6K]

Answer:

$10.50/1.25 = $10.20

Step-by-step explanation:

hope this helps

5 0

3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago

Solve each system by substitution x^2 − 14x + 49 = 4?