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3 years ago

Find the slope of the line whose equation is 5y = x - 3.

2 answers:

4 0

Y=mx+b
m=slope
so we just have to convert it to such
5y=x-3
sivide both sides by 5 to get 1y
y=1/5x-3/5
y=mx+b
m=1/5
slope=1/5

Musya8 [376]3 years ago

3 0

Easy,

it's already good, written in y=mx+b form

m=slope

You have,

5y=x-3

Divide by 5 to isolate the y

$\frac{5y}{5}= \frac{x}{5}- \frac{3}{5}$

Making it,

y= $\frac{1}{5} x- \frac{3}{5}$

The slope,m, is $\frac{1}{5}$ .

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Solve the following for the specified variable Z=s/2(P+p); for P

lapo4ka [179]

Answer:

$\boxed{\sf P = \frac{2Z}{s} - p}$

Step-by-step explanation:

$\sf Solve \ for \ P: \\ \sf \implies Z = \frac{s}{2} (P + p) \\ \\ \sf Z = \frac{s}{2} (P + p) \ is \ equivalent \ to \ \frac{s}{2} (P + p) = Z: \\ \sf \implies \frac{s}{2} (P + p) = Z \\ \\ \sf Divide \ both \ sides \ by \ \frac{s}{2} : \\ \sf \implies P + p = \frac{2Z}{s} \\ \\ \sf Substrate \ p \ from \ both \ sides: \\ \sf \implies P = \frac{2Z}{s} - p$

6 0

3 years ago

find the slope of the line that has the following intercepts: y-intercept: -15; x-intercept: 3. round your answer to 1 decimal p

Readme [11.4K]

Y intercept : (0,-15)
X intercept : (3,0)

Slope : (0 - (-15)) / (3-0) = 15 / 3 = 5

3 0

3 years ago

In this diagram, EA−→−⊥ ED−→− and EB−→− bisects ∠AEC . Given that m∠AEB = 4x + 1 and m∠CED = 3x, determine the missing measures.

alexdok [17]

Answer:

Step-by-step explanation:

8,33

7 0

3 years ago

Pls pls help Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

_____

Comment on the figure

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

5 0

3 years ago

Carl and rose live in the same straight road. From their balconies they can see a flagpole in the distance. The angle that each

Andreyy89

Carl and Rose' balconies make up the base of an isosceles triangle.

Their distances from the flagpole is the same.

From the question, we understand that:

Carl and Rose live on a straight line
The measure of angle from each person's balcony to the flagpole is the same

The above highlights mean that:

The relationship between Carl and Rose' balconies and the flagpole is an isosceles triangle.

Where Carl and Rose' balconies form the base of the isosceles triangle.

Hence, their distances from the flagpole is the same.