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3 years ago

13

There's got to be someone who can answer this

1 answer:

Sphinxa [80]3 years ago

4 0

Yes based on ja 82 and it can be added

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Find the sum. 2x^2 +26x+ 156=0

Mila [183]

Answer:

-13

Step-by-step explanation:

2x²+26x+156=0

x²+13x+78=0

x²+13x=-78

x²+13x+169/4=-143/4

(x+13/2)²=-143/4

x+13/2=(i√143)/2 or x+13/2=-(i√143)/2

x=(i√143)/2-13/2 or x=-(i√143)/2-13/2

(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13

5 0

3 years ago

Read 2 more answers

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Kobotan [32]

Keep sonsobsonsonsnisniunwun of your name and I will have to be a blind

8 0

3 years ago

Whats 21/40 in equivalent decimals

GREYUIT [131]

The equivalent decimals for 21/40 is 0.525

5 0

3 years ago

Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}

sashaice [31]

Hey there!

Assuming you meant

$5r^2 - 12 = 68$

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to $add$ by $12$ on each of your sides

$5r^2 -12 +12 \\ \\ 68 + 12$

$5r^2 = 5r^2 \\ \\ 68 + 12 = 80$

We get: $5r^2 =80$

Now, we have $divide$ by $5$ on each of your sides

$\frac{5r^2}{5} = \frac{80}{5}$

$\frac{80}{5} = 16$

We get: $r^2 = 16$

$r =$ ± $\sqrt{16}$

Therefore , your answer is: $r =$ ± $4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

3 0

3 years ago

For each of the following sequences, • Give a formula for the nth term in the sequence, • Give a recursive definition for the se

Andrew [12]

Answer:

(a) $n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) $n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

(c) $n^{th} = n!$

$f(1) = 1$

$f(n) = f(n-1) * n$

Step-by-step explanation:

(a) This is a sequence of consecutive number

$n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) This is a sequence of 2 to the power of n - 1. The next number is twice time of this number

$n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

(c) This is factorial sequence. Where the next number is this number multiplied by $n^{th}$

$n^{th} = n!$

$f(1) = 1$

$f(n) = f(n-1) * n$

5 0

3 years ago