Answer:
8 green tshirts
Step-by-step explanation:
Try comparing your solution with the following:
Solution:
Answer:
Check:
![2[10-13(\frac{40}{17})]+9(\frac{40}{17})=-34(\frac{40}{17})+60\\-20=-20](https://tex.z-dn.net/?f=2%5B10-13%28%5Cfrac%7B40%7D%7B17%7D%29%5D%2B9%28%5Cfrac%7B40%7D%7B17%7D%29%3D-34%28%5Cfrac%7B40%7D%7B17%7D%29%2B60%5C%5C-20%3D-20)
<em>Hope this was helpful.</em>
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Answer:
Both child tickets and senior tickets cost $14.
Step-by-step explanation:
Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:
10 senior tickets + 8 child tickets = 252
10 senior tickets + 10 child tickets = 280
280 - 252 = 2 child tickets
28 = 2 child tickets
28/2 = 1 child ticket
14 = 1 child ticket
14 x 10 = 140
(280 - 140) / 10 = senior tickets
140/10 = 14 = senior tickets
Therefore, both child tickets and senior tickets cost $14.
