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Nikitich [7]
3 years ago
12

Which is true of a melting point and a boiling point?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

B - The melting point is a lower temperature than the boiling point.

Step-by-step explanation:

Melting point is the temperature at which any given solid will melt. The state of the solid changes from solid to liquid.

Boiling point is the temperature at which a given liquid boils and changes to vapor state. Like water starts to boil at 100 degrees Celsius.

The boiling point of a substance cannot be lower than its melting point.

So, the answer here is - The melting point is a lower temperature than the boiling point.

Rasek [7]3 years ago
6 0
I believe it should be B
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Which shows the list of numbers in order from least to greatest?
nirvana33 [79]

Answer:

-1, |-2|, |-3|, |3.5|, |3²|

Step-by-step explanation:

  • Calculate the absolute value (the absolute value of any number is always positive): 3, 3², 2 , 3.5, -1
  • Calculate the exponents : 3, 9, 2 , 3.5, -1
  • Put in order least to greatest : -1, |-2|, |-3|, |3.5|, |3²|
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3 years ago
The set of ordered pairs below represents a linear function.
vivado [14]

Answer:

(4,0)

Step-by-step explanation:

It is a linear function so you find the slope by doing y2-y1/x2-x1 and you find the slope to be 1/2. You can then setup an equation using it and graph it to find the next value.

7 0
3 years ago
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The answer is 114 x
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Solve for w: -4u-w = u+6w
wlad13 [49]

Answer:

A

Step-by-step explanation:

-4u - w = u + 6w

-4u = u + 7w  (Add w to both sides)

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w = -\frac{5u}{7} (Divide both sides by 7)

8 0
3 years ago
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A box has five items, three good and two defective. three items are selected at random without replacement. let x be the number
user100 [1]
This problem can be solved from first principles, case by case.  However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.

Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then 
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where 
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected

Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}

Therefore the 
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}

7 0
3 years ago
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