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Anna11 [10]
3 years ago
12

Please answer thank you!

Mathematics
2 answers:
vivado [14]3 years ago
8 0

Answer:

C

Step-by-step explanation:

dangina [55]3 years ago
3 0
C is the answer because -2+16=14 and 9x+x=10x
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How do you solve this (−18) ÷ 3 + (5)(−2) ?
Alekssandra [29.7K]
<span>(−18) ÷ 3 + (5)(−2)
Multiply 5 by -2
(-18)/3 -10
Divide -18 by 3
-5-10
Subtract 10 from -5
Final Answer: -15</span>
6 0
4 years ago
A car manufacturer announced that next year the price of a certain model car would increase by 5.5%. This year the price is $15,
Sunny_sXe [5.5K]
You have to multiply the previous year $ with 5.5% or 0.055 (they're the same) .The price would increase by 849.91500 so when you add the previous price with the 849.91500, you would get $16302.915
3 0
3 years ago
Find the unit rate of 20 meters/4 minutes
salantis [7]

Answer:

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8 0
3 years ago
Bob bought a megahunk chocolate bar that weighed 9/10 lb he has already eaten 1/3 lb how much chocolate dose he have left
torisob [31]

Hi there! :)

<u>Answer:</u>

The answer is B) 17/30


Step-by-step explanation:

In order to find your answer you need to subtract 1/3 from 9/10:

9/10 - 1/3 = chocolate left

Since theses fractions do not have the same denominators (bottom number), the key here is to rewrite both of the fractions so that they have the same denominator:

The denominator is going to be a common multiple of "10" and "3". Ideally it's going to be the <u>least common multiple</u> of "10" and "3".

Let's start with the larger of the two denominators, which is "10". You have to go through its multiples and and see when we get to one that's divisible perfectly by 3.

So 10 is not divisible perfectly by 3, neither is 20. 30 on the other hand is divisible perfectly by 3. 30 is three times 10.

So you can rewrite both of these fractions as something over 30.

1/3 = ?/30

To get from 3 to 30, we have to multiply by 10. So if you multiply the denominator by 10, if you don't want to change the value of the fraction, you have to multiply the numerator (top number) by 10 also.

1/3 = <u>10/30</u>

Same thing with the other fraction:

9/10 = ?/30 → 3 × 10 = 30 / SO, you need to multiply the numerator by three also → 9 × 3 = 27

9/10 = <u>27/30</u>


Now that your fractions both have the same denominator, you can subtract the numerators together and put the answer on 30.

27/30 - 10/30 = ?

27 - 10 = 17 → <u>17/30</u>


Since the fraction is simplified, you are now done.


There you go! I really hope this helped, if there's anything just let me know! :)

8 0
4 years ago
A tank contains 9,000 L of brine with 18 kg of dissolved salt. Pure water enters the tank at a rate of 90 L/min. The solution is
aev [14]

Let <em>x(t)</em> denote the amount of salt (in kg) in the tank at time <em>t</em>. The tank starts with 18 kg of salt, so <em>x</em> (0) = 18.

The solution is drained from the tank at a rate of 90 L/min, so that the amount of salt in the tank changes according to the differential equation

d<em>x(t)</em>/d<em>t</em> = - (<em>x(t)</em> kg)/(9000 L) × (90 L/min) = -1/100 <em>x(t)</em> kg/min

or, more succintly,

<em>x'</em> = -1/100 <em>x</em>

This equation is separable as

d<em>x</em>/<em>x</em> = -1/100 d<em>t</em>

Integrating both sides gives

∫ d<em>x</em>/<em>x</em> = -1/100 ∫ d<em>t</em>

ln|<em>x</em>| = -1/100 <em>t</em> + <em>C</em>

<em>x</em> = exp(-1/100 <em>t</em> + <em>C </em>)

<em>x</em> = <em>C</em> exp(-<em>t</em>/100)

(a) Using the initial condition <em>x</em> (0) = 18, we find

18 = <em>C</em> exp(0)   ==>   <em>C</em> = 18

so that

<em>x(t)</em> = 18 exp(-<em>t</em>/100)

(b) After 20 minutes, we have

<em>x</em> (20) = 18 exp(-20/100) = 18 exp(-1/5) ≈ 14.74

so the tank contains approximately 14.74 kg of salt after this time.

7 0
3 years ago
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