<span><span>(<span>23</span>)</span><span>−3</span></span><span><span><span>
</span></span></span><span><span><span>(<span>32</span>)</span>3
</span></span><span><span><span><span>(<span>32</span>)</span>*<span>(<span>32</span>)</span></span>*<span>(<span>32</span>)
</span></span></span><span><span><span><span>3*3</span>*3</span><span><span>2*2</span>*2</span></span></span><span>=<span><span>33</span><span>23
</span></span></span><span><span><span>278</span></span><span>(Decimal: 3.375)</span></span>
A linear equation is an equation in which the highest power of the variable is always
Hi how u doin boi the answer id 6555555
Answer:
A
Step-by-step explanation:
Answer:
Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable
Part 2) The number of minutes in a month must be equal to 50 minutes
Step-by-step explanation:
<u><em>The question is</em></u>
Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute
Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan
Part 1)
Let
x ---> the number of minutes
we have
<em>Cost Plan A</em>

<em>Cost Plan B</em>

we know that
In order for plan A to be cheaper than plan B, the following inequality must hold true.
cost of plan A < cost of plan B
substitute

solve for x
subtract 3x both sides

divide by 2 both sides

Rewrite

therefore
The number of minutes in a month must be greater than 50 in order for the plan A to be preferable
Part 2)
Let
x ---> the number of minutes
we have
<em>Cost Plan A</em>

<em>Cost Plan B</em>

we know that
In order for plan A cost the same than plan B, the following equation must hold true.
cost of plan A = cost of plan B
substitute

solve for x

therefore
The number of minutes in a month must be equal to 50 minutes