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SashulF [63]
4 years ago
6

L'shanda can choose between 3 sweaters and 4 skirts. if she selects 1 sweater and 1 skirt, how many possible outcomes are in the

sample space answer
Mathematics
2 answers:
omeli [17]4 years ago
8 0
Nuber of outcomes = 3 * 4  = 12 Answer
steposvetlana [31]4 years ago
3 0

We have been given that L'shanda can choose between 3 sweaters and 4 skirts.

We need to figure out the number of ways in which L'shanda can pick 1 sweater and 1 skirt out of the available items.

We need to use combinations here. First of all, we will figure out the number of ways of choosing 1 sweater out of 3 available sweaters. And then we will determine the number of ways of choosing 1 skirt out of 4 available skirts.

Number of ways of choosing 1 sweater = _{1}^{3}\textrm{C}=\frac{3!}{2!1!}=\frac{3\cdot 2!}{2!} = 3

Number of ways of choosing 1 skirt = _{1}^{4}\textrm{C}=\frac{4!}{3!1!}=\frac{4\cdot 3!}{3!} = 4

Therefore, total number of ways to select 1 sweater and 1 skirt are 3\cdot 4 = 12


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The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

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