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3 years ago

What would you do if you had $50 million ? <3 ;)

Mathematics

2 answers:

kramer3 years ago

5 0

Answer:

I wouold buy a house first then pay it off and give the rest of the money to my parents as a gift.

Step-by-step explanation:

UkoKoshka [18]3 years ago

3 0

Answer: I would donate most of it, buy a nice big house, expensive cars, buy the most strongest PC and have the best gaming setup, get the best training equipment for soccer, build mosque's, help kids and poor people around the world, and hopefully get more money, and be the best soccer player.

Step-by-step explanation:

You might be interested in

Which pair of numbers are not opposites?

mrs_skeptik [129]

Answer:

The answer is C, 17 and | -17|

Step-by-step explanation:

We can solve this using the process of elimination.

Looking at the first one, we know that those | | around the 7 mean to find the absolute value. The absolute value is the number of units the number is from zero, and it is always positive. This means that it is saying 7 and -7. Those are opposites, so we know that this isn't right.

17 and -17 are opposites, since the opposite of a positive is a negative.

The last one is the same. 71 and -71 are opposites. That leaves us with C.

Remember that those | | mean to find the absolute value of. -17 is 17 unites from zero. So is 17 the oppostie of 17? No, so these are not opposites, and therefore are our answer.

8 0

2 years ago

Read 2 more answers

A game has an expected value to you of $100. it costs $500 to play, but if you win you receive $100,000 (including your $50

tekilochka [14]

Let $X$ be a random variable denoting the amount of winnings in any given round of the game. There is some probability $p$ of winning where $P(X=99,500)=p$ , while $P(X=-500)=1-p$ , assuming these are the only two possible outcomes. So we have

$\mathbb E[X]=\displaystyle\sum_xxP(X=x)=99,500p-500(1-p)=100$

$100,000p-500=100\implies p=\dfrac3{500}=0.006$

8 0

3 years ago

What decimal is equal to 7/9

nekit [7.7K]

7/9 = 0.77777778

honestly i just googled this

6 0

3 years ago

Read 2 more answers

Find the product of (x − 5)^2.

Alex17521 [72]

(x - 5)^2 =
(x - 5)(x - 5) =
x^2 - 5x - 5x + 25 =
x^2 - 10x + 25 <===

8 0

2 years ago

Item 7

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

2 years ago