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dybincka [34]
3 years ago
10

Is this a difference of squares? x2−30

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

we know that

<u>The difference of squares</u> is two terms that are squared and separated by a subtraction sign

so

a^{2}-b^{2}=(a+b)*(a-b)

<u>Part a) </u>

we have

x^{2}-30

we know that

\sqrt{30} -------> is not a integer

so

The number 30 is not a perfect square number

therefore

<u>the answer part a) is the option</u>

4. No because the 30 is not a perfect square number

<u>Part b) </u>

we have

(16x^{2}-25)

we know that

16x^{2}=(4x)^{2} \\25=5^{2}

so

(16x^{2}-25)=(4x)^{2}-5^{2}=(4x+5)*(4x-5)

therefore

<u>the answer part b) is the option</u>

2. (4x−5)(4x+5)


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Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

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              1  4  6  4   1                      n=4

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Now we want to expand:

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Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

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=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

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