Is this a difference of squares? x2−30
1 answer:
we know that
<u>The difference of squares</u> is two terms that are squared and separated by a subtraction sign
so

<u>Part a) </u>
we have

we know that
-------> is not a integer
so
The number 30 is not a perfect square number
therefore
<u>the answer part a) is the option</u>
4. No because the 30 is not a perfect square number
<u>Part b) </u>
we have

we know that

so

therefore
<u>the answer part b) is the option</u>
2. (4x−5)(4x+5)
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Answer:

Step-by-step explanation:

You have to prime factorise 81 and then you will get <u>9</u> as the answer.
0.8 is greater because it is a positive number..
Answer
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6:11 because polygons have 4 side so it would be 24:44 but it just reduces back to 6:11. hope this helped have a good day!!