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Phantasy [73]
3 years ago
10

Two years ago Sarah put money in a simple interest account that earned

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer:

<u>7000</u>

We have: I = P × R × T / 100

Here, I = 980

P = 7000

T = 8

Substitute their values into the expression:

980 = 7000 × R × 8 / 100

R = 980 × 100 / 7000 × 8

R = 98000 / 56000

R = 1.75%

In short, Your Answer would be 1.75%

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Ms speakman's smartphone is on sale for 25% off its list price. The sale priceof the smartphone is 51799,99, What expression can
Ber [7]

The expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925

<h3>What expression can be used to represent the list price of the smartphone? </h3>

The given parameters are:

Discount = 25%

Sales price = 5179.99

The expression that can be used to represent the list price of the smartphone is

Expression = Sales price * (1- discount)

So, we have:

Expression = 5179.99 * (1- 25%)

Evaluate

Expression = 3884.9925

Hence, the expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925

Read more about discounts at:

brainly.com/question/7459025

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3 0
1 year ago
I need help with this question.
Kitty [74]

i'm not sure how to solve the first one but the second is 150

4 0
3 years ago
Pleease help me with this math work
OleMash [197]
The first one because the left bound is included [ and the right one is not )
6 0
3 years ago
Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,
miskamm [114]

The mean deviation of the ratings is  4.12

<em><u>Explanation</u></em>

The ratings of the ten experts are:  34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings =\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9

<u>The formula for Mean deviation</u> = \sum \frac{|x_{i}- \mu|}{N} , where x_{i} is the given data from i=1 to i=10 , \mu is the mean of the data and N is the total number of data. So.....

|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1

So, the Mean deviation =\sum \frac{|x_{i}-\mu |}{N}=\frac{0.1+1.1+7.1+5.9+7.9+4.9+1.9+2.1+4.1+6.1}{10} = \frac{41.2}{10}=4.12

4 0
3 years ago
When round off to nearest thousand, the number 42,099​
Roman55 [17]

Answer:42000

Step-by-step explanation:

There is no number higher than 5 after the thousands so you would keep it the same

3 0
2 years ago
Read 2 more answers
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