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LenKa [72]
3 years ago
13

T/2 + 3 = 5 (solve for t)

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

t = 4

Step-by-step explanation:

Given

\frac{t}{2} + 3 = 5 ( subtract 3 from both sides )

\frac{t}{2} = 2

Multiply both sides by 2 to clear the fraction

t = 2 × 2 = 4

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g Consider the experiment of a single roll of an honest die and a single toss of 3 fair coins. Let X be the value on the die and
klemol [59]

Answer:

The probability function of X and Y is

P(X = k, Y = 0)  = 1/48\\P(X = k, Y = 1) = 1/16\\P(X = k, Y = 2) = 1/16\\P(X = k, Y = 3) = 1/48

With k in {1,2,3,4,5,6}

Step-by-step explanation:

We can naturally assume that X and Y are independent. Because of that, P(X=a, Y=b) = P(X=a) * P(Y=b) for any a, b.

Note that, since the die is honest, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. We can conclude as a consequence that P(X=k, Y=l) = P(Y=l)/6 for any k in {1,2,3,4,5,6}.

Y has a binomial distribution, with parameters n = 3, p = 1/2. Y has range {0,1,2,3}. Lets compute the probability mass function of Y:

P_Y(0) = {3 \choose 0} * 0.5^3 = 1/8

P_Y(1) = {3 \choose 1} * 0.5* 0.5^2 = 3/8

P_Y(2) = {3 \choose 2} * 0.5^2*0.5 = 3/8

P_Y(3) = {3 \choose 3} * 0.5^3 = 1/8

Thus, we can conclude that the joint probability function is given by the following formula

P(X = k, Y = 0) = 1/8 * 1/6 = 1/48\\P(X = k, Y = 1) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 2) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 3) = 1/8 * 1/6 = 1/48

For any k in {0,1,2,3,4,5,6}

4 0
3 years ago
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