The value of the truck initially, Ao is
83000
1-0.16=0.84
1-0.26=0.74
After one year the value
Y=83,000×(0.84)=69,720
Y=83,000×(0.74)=61,420
When you compare the results you will see that the graph would fall at a faster rate to the right because the depreciation rate of 26% is higher than the depreciation rate of 16%
Hope it helps
You want to know how long it'll take for the bacteria to grow
to (800/500) = 1.6 times their initial population.
The number of double-times it'll take is
[ log(1.6) / (log(2) ] = 0.6781 .
The double-time for these particular critters is 12 hours,
so it'll take them
0.6781 x 12 hours = 8.137 hours
= 8 hours 8.2 minutes .
Solve either equation for either variable. Since the second one has y on its own, the easiest choice is to solve that for y.
-5x + y = 13 ⇒ y = 5x + 13
Now substitute this into the other equation to eliminate y and rewrite it entirely in terms of x :
-3x + 3y = 3 ⇒ -3x + 3 (5x + 13) = 3
Simplify and solve for x :
-3x + 15x + 39 = 3
12x = -36
x = -3
Substitute this into either original equation to solve for y. Plugging x = -3 into the first equation would give
-3 (-3) + 3y = 3
9 + 3y = 3
3y = -6
y = -2
So the solution to the system of equations is (x, y) = (-3, -2).
Hello there! Your answer would be 1/4.
So to start, count up the total number of sections, and the number of red sections. There are 16 sections total, and 4 of them are red.
This can give us the ratio 4/16.
But next we need to simplify. What is the biggest number that can be divided by both 4 and 16? 4. So, divide both 4 and 16 by 4 to get your simplified answer.
4÷4/16÷4
1/4
So, the ratio of red sections to total sections, in lowest terms is 1/4.
