The carbon 14 left from this animal is 3 grams of 24 grams which is: 3g/24g= 1/8 times of its original mass. Then, the age of the animal fossil would be:
final weight= initial weight * (1/2) ^ time/half-live
1/8 initial weight = initial weight * (1/2) ^ time/half-live
log2 1/8= log2 (1/2) ^ time/half-live
-3= -time/half-live
time= -3 * -(half-live)
time= 3 half-live
If the half-live is 5730 years, the age would be: 3* 5730= 17.190 years.
The answer is preserving biodiversity. It can be well-defined as the biological changeability among all living plants and animals of the earth as an outcome of the evolution procedures and contains of three levels of biological diversity which are genetic diversity, species diversity and ecosystem diversity.
Answer:
Partial nitrate reduction results in the formation of nitrite and water
Explanation:
Answer:
Mocous cell
Explanation:
literally, stomach have chief cell (zymogenic), parietal cell and mocous cell
Answer:
B. the hormone must enter the cell
